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Did everybody see that? As a result of I cannot be doing it once more
Some of the enjoyable (and irritating) methods to play an outdated favourite is attempting to finish a self-imposed problem that basically ratchets up the problem. For me, it was beating a run in Hades on 32 warmth — for others, it is likely to be finishing a Darkish Souls run with out taking harm or doing a Nuzlocke of a favourite Pokémon sport. Once you love a sport sufficient to place the hours in that you have to full a problem like this, you’d be stunned at how a lot you’ll be able to accomplish — and by how triumphant it feels whenever you lastly beat it. I think about that streamer Jervalin is using even greater after successful a $20,000 money prize for beating a near-impossible problem in Halo 2.
The problem? Beating the Halo 2 marketing campaign on its Legendary problem setting, whereas additionally enabling all Skulls (besides Envy), with out dying. These Skulls are collectibles that gamers can discover all through the degrees within the marketing campaign, however extra importantly, they unlock hidden gameplay modifiers to make the sport much more crushingly tough. Their results will be something from giving enemies extra well being, making your HUD and weapons invisible, and making enemies explode whenever you headshot them. There are fifteen complete Legendary Skulls within the sport, so this problem will not be for the faint of coronary heart.
Jervalin streamed his whole Legendary Skulls no-death run on Twitch, which clocked in at almost seven hours. So far as we all know, he’s the one one to have ever accomplished this problem, which is a reasonably large deal contemplating Halo 2 got here out in 2004. YouTube character and streamer Charlie “Cr1tikal” White was the one to supply prize cash for finishing the run, in any other case often called the “Moist Cr1tikal Problem.”
It’s fairly cool that White held up his finish of the cut price, and I feel that goes to indicate how spectacular Jervalin’s LASO (Legendary All Skulls On) playthrough actually is.
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